0=2x^2-8x+10

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Solution for 0=2x^2-8x+10 equation: 



0=2x^2-8x+10

We move all terms to the left:

0-(2x^2-8x+10)=0

We add all the numbers together, and all the variables

-(2x^2-8x+10)=0

We get rid of parentheses

-2x^2+8x-10=0

a = -2; b = 8; c = -10;
Δ = b2-4ac
Δ = 82-4·(-2)·(-10)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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